SQL - Programming Help

SQL – Design and Analysis of Data Systems

— phpMyAdmin SQL Dump
— version 4.9.2
— https://www.phpmyadmin.net/

— Host: 127.0.0.1
— Generation Time: Apr 06, 2020 at 01:56 PM
— Server version: 10.4.11-MariaDB
— PHP Version: 7.2.26

SET SQL_MODE = “NO_AUTO_VALUE_ON_ZERO”;
SET AUTOCOMMIT = 0;
START TRANSACTION;
SET time_zone = “+00:00”;
/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8mb4 */;


— Database: `oltp`

— ——————————————————–


— Table structure for table `adventureworks`

CREATE TABLE `adventureworks` (
`ID` int(10) NOT NULL,
`Name` varchar(35) NOT NULL,
`Bike` varchar(35) NOT NULL,
`Model` varchar(35) NOT NULL,
`Color` varchar(35) NOT NULL,
`Year` year(4) NOT NULL,
`Sold` varchar(35) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;


— Dumping data for table `adventureworks`

INSERT INTO `adventureworks` (`ID`, `Name`, `Bike`, `Model`, `Color`, `Year`, `Sold`) VALUES
(10, ‘Brown’, ‘Honda’, ‘H789’, ‘Red’, 2002, ‘Yes’),
(11, ‘Lucy’, ‘Adventure’, ‘A345’, ‘Blue’, 2003, ‘Yes’),
(12, ‘Alfreds’, ‘Flyer’, ‘F567’, ‘Black’, 2004, ‘Yes’),
(13, ‘Kaze’, ‘Activa’, ‘A345’, ‘Red’, 2003, ‘No’),
(14, ‘Lucy’, ‘Adventure’, ‘A345’, ‘Blue’, 2003, ‘No’),
(15, ‘Alfreds’, ‘Flyer’, ‘F567’, ‘Black’, 2004, ‘No’),
(16, ‘Kaze’, ‘Activa’, ‘A345’, ‘Red’, 2003, ‘Yes’),
(17, ‘Brown’, ‘Honda’, ‘H789’, ‘Red’, 2002, ‘No’),
(18, ‘Lucy’, ‘Adventure’, ‘A345’, ‘Blue’, 2003, ‘Yes’),
(19, ‘Alfreds’, ‘Flyer’, ‘F567’, ‘Black’, 2004, ‘No’),
(20, ‘Kaze’, ‘Activa’, ‘A345’, ‘Red’, 2003, ‘Yes’);

— ——————————————————–


— Table structure for table `customer`

CREATE TABLE `customer` (
`customerID` varchar(35) NOT NULL,
`ID` int(10) NOT NULL,
`Name` varchar(35) NOT NULL,
`Address` varchar(35) NOT NULL,
`State/province` varchar(35) NOT NULL,
`Email` varchar(35) NOT NULL,
`SalesVolume` varchar(35) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;


— Dumping data for table `customer`

INSERT INTO `customer` (`customerID`, `ID`, `Name`, `Address`, `State/province`, `Email`, `SalesVolume`) VALUES
(‘C12’, 10, ‘Brown’, ‘Near Park 6’, ‘Newyork’, ‘brown@gmail.com’, ‘789’),
(‘C13’, 14, ‘Lucy’, ‘London near street 6’, ‘London’, ‘lucy@gmail.com’, ‘890’),
(‘C14’, 15, ‘Alfreds’, ‘South Carolina’, ‘South Est’, ‘a1@gmail.com’, ‘440’),
(‘C15’, 16, ‘Kaze’, ‘Near water park’, ‘London’, ‘ka@gmail.com’, ‘900’),
(‘C16’, 10, ‘Brown’, ‘Near Park 6’, ‘Newyork’, ‘brown@gmail.com’, ‘200’),
(‘C17’, 14, ‘Lucy’, ‘London near street 6’, ‘London’, ‘lucy@gmail.com’, ‘345’),
(‘C18’, 15, ‘Alfreds’, ‘South Carolina’, ‘South Est’, ‘a1@gmail.com’, ‘500’),
(‘C19’, 16, ‘Kaze’, ‘Near water park’, ‘London’, ‘ka@gmail.com’, ‘345’);

— ——————————————————–


— Table structure for table `dimemployee`

CREATE TABLE `dimemployee` (
`EmpID` varchar(35) NOT NULL,
`Name` varchar(35) NOT NULL,
`Address` varchar(35) NOT NULL,
`LoginID` varchar(35) NOT NULL,
`Password` varchar(35) NOT NULL,
`BikeID` varchar(35) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;


— Dumping data for table `dimemployee`

INSERT INTO `dimemployee` (`EmpID`, `Name`, `Address`, `LoginID`, `Password`, `BikeID`) VALUES
(‘E123’, ‘Tom Cru’, ‘Near Kk park’, ‘tw@gmail.com’, ‘123’, ’10’),
(‘E124’, ‘Maze’, ‘Water parrk’, ‘m@gmail.com’, ‘567’, ’11’),
(‘E125’, ‘Maze’, ‘Water parrk’, ‘m@gmail.com’, ‘567’, ’11’),
(‘E126’, ‘Tomy Cru’, ‘Near Kk park’, ‘tw@gmail.com’, ‘123’, ’12’),
(‘E127’, ‘Malle’, ‘Water parrk’, ‘m@gmail.com’, ‘567’, ’14’),
(‘E128’, ‘Toy Cru’, ‘Near Kk park’, ‘tw@gmail.com’, ‘123’, ’10’),
(‘E129’, ‘Maze’, ‘Water parrk’, ‘m@gmail.com’, ‘567’, ’15’),
(‘E130’, ‘Tom Cru’, ‘Near Kk park’, ‘tw@gmail.com’, ‘123’, ’19’),
(‘E131’, ‘Maze’, ‘Water parrk’, ‘m@gmail.com’, ‘567’, ’16’),
(‘E132’, ‘Tom Cru’, ‘Near Kk park’, ‘tw@gmail.com’, ‘123’, ’10’);


— Indexes for dumped tables


— Indexes for table `adventureworks`

ALTER TABLE `adventureworks`
ADD PRIMARY KEY (`ID`);


— Indexes for table `customer`

ALTER TABLE `customer`
ADD PRIMARY KEY (`customerID`);


— Indexes for table `dimemployee`

ALTER TABLE `dimemployee`
ADD PRIMARY KEY (`EmpID`);
COMMIT;

/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;

7 Tips to solve complex programming assignments

7 Tips To Solve Complex Programming Assignments

Every Programming Assignment given to a software developer is meant to see how well they can program and even it is given to ensure that he or she adheres to the practices and the writing of code which the person who is reviewing it will want to work with.

These coding and programming challenges come with written instructions which need to be carefully read so that they are understood in totality. Continue reading

All Assignment Experts - Java Assignment Help

7 Reasons Why Students Ask For Java Assignment Help

Java is probably one of the most sought after options as it plays a major part in the creation of professional applications. However, being popular doesn’t mean that it is an easy job. Most students struggle with learning Java, especially in the very beginning. Assignments can be quite intensive as well due to the concepts. More than anything, the programming part is quite complicated. Continue reading